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[(x/3)/12]十[(2╳/3)/30+ 0,5=(3╳/5)/12 (2╳/5)/30...

y=x^3-5x^2+3x+5 y'=3x^2-10x+3 y"=6x-10 =2(3x-5) y"=0 2(3x-5)=0 x=5/3 y=(5/3)^3-5×(5/3)^2+3×5/3+5 =125/27-125/9+5+5 =250/27+10 =520/27 y"

约定:∫[a,b]表示[a,b]上的定积分 x>0时 x/(x^3+16)=x/(x^3+8+8) ≤x/(3(x^3·8·8)^(1/3)) (用到3次均值不等式) =x/(12x) =1/12 ∫[0,10](x/(x^3+16))dx ≤∫[0,10](1/12)dx =(x/12)|[0,10] =5/6 所以∫[0,10](x/(x^3+16))dx≤5/6 希望能帮到你!

=[-12×(2/3+1/3)]-0.34×(2/7+5/7) =-12×1-0.34×1 =-12-0.34 =-12.34

syms x y=3^3+(x-0.98)^2/(x+1.35)^3-5*(x+1/x) y=subs(y,x,2)

这道题要求计算能力很强 3/x+1/(x-1)+4/(x-2)+4/(x-3)+1/(x-4)+3/(x-5)=0 [3/x+3/(x-5)]+[1/(x-1)+1/(x-4)]+[4/(x-2)+4/(x-3)]=0 (6x-15)/(x^2-5x)+(2x-5)/(x^2-5x+4)+(8x-20)/(x^2-5x+6)=0 (2x-5)[3/(x^2-5x)+1/(x^2-5x+4)+4/(x^2-5x+6)]=0 所...

0.5x(3/5+6/25) =0.5×3/5×(1+2/5) =3/10×7/5 =21/51

解:1)由函数图像可知:A=2 T=4*[π/6-(-π/6)]=4π/3 ∴w=2π/(4π/3)=1.5 ∴f(x)=2sin(1.5x+φ) 把(π/6,2)代入函数解析式得: 2sin(1.5*π/6+φ)=2 ∵0

你只看Y2的数据就可以了,我以前帮别人做过这个题目。Y1=0.5X+1,Y2=(X+1)^2,所以你只看Y2的解答就可以了。

函数y=2x^3-3x^2-12x+5 利用导函数y'=6(x^2-x-12)=6(x+1)(x-2) 即x在[0,2]上是减函数,[2,正无穷)为增函数。 所以函数y=2x^3-3x^2-12x+5在[0,3]上的最小值为 f(2)=2*2^3-3*2^2-12*2+5 = -15 最大值有可能为0或3,f(0)=5,f(3)= -4 所以最大值为f(...

1]1.5x=6x12 x=48 2]5/6x=0.5x1/3 x=1/5 3]2x=5/6x3/10 x=1/8 4]x=7/2

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