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解方程:①1%2(2x+3)=%3(2x+1)②x[x(x%9...

①x2+2x-99=0,(x+11)(x-9)=0,x+11=0,x-9=0,x1=-11,x2=9.②(2x-1)2=x(6x-3),(2x-1)2-3x(2x-1)=0,(2x-1)(2x-1-3x)=0,2x-1=0,2x-1-3x=0,x1=12,x2=-1.③4x2-8x+1=0,b2-4ac=(-8)2-4×4×1=48,x=8±482×4,x1=2+32,x2=2?3...

(3x+1)^2=9(2x+3)^2 (3x+1)²=[3(2x+3)]² 3x+1=±3(2x+3)=±(6x+9) ∴3x+1=6x+9→3x=-8→x=-8/3 3x+1=-6x-9→9x=-10→x=-10/9

(1)因式分解得,(2x+1)(x+3)=0,解得,x1=12,x2=3;(2)移项得,(x-1)2+2(x-1)=0,提公因式得,(x-1)(x-1+2)=0,解得,x1=1,x2=-1;(3)移项得,x(2x+3)-(4x+6)=0,提公因式得,(2x+3)(x-2)=0,解得,x1=-32;x2=2;...

(1)移项得,2x-5x=7+9+3,合并同类项得,-3x=19,系数化为1得,x=- 19 3 ;(2)去分母得,3(x-3)-5(x-4)=15,去括号得,3x-9-5x+20=15,移项得,3x-5x=15+9-20,合并同类项得,-2x=4,系数化为1得,x=-2.

2x+5/9*2x=2 2x+10/9x=2 28/9x=2 x=2*9/28 x=9/14

解:(1) x²+2x+1=9 x²+2x-8=0 (x+4)(x-2)=0 x1=-4 x2=2 ② x²-2x-3=0 (x-3)(x+1)=0 x1=-1 x2=3

(1)移项、合并同类项得:-3x=19,系数化1得:x=-193;(2)去括号得:8x+12=8-5x+10,移项、合并同类项得:13x=6,系数化1得x=613;(3)去分母得:3(4-x)-2(2x+1)=6,去括号得:12-3x-4x-2=6,移项、合并同类项得:-7x=-4,系数化1得x=...

(1)开方得:2x-3=3(2x+3)或2x-3=-3(2x+3),解得:x1=-3,x2=-34;(2)分解因式得:(2x-6)(x-1)=0,可得2x-6=0或x-1=0,解得:x1=3,x2=1;(3)方程变形得:(5x-1)2-3(5x-1)=0,分解因式得:(5x-1)(5x-1-3)=0,解得:x1=0.2...

①∵(2x-1) 2 =9,∴2x-1=±3,∴2x-1=3或2x-1=-3,∴x 1 =2,x 2 =-1;②由原方程,得x 2 +3x=4,等式的两边同时加上一次项系数一半的平方,得x 2 +3x+ 9 4 =4+ 9 4 ,即(x+ 3 2 ) 2 = 25 4 ,直接开平方,得x+ 3 2 =± 5 2 ,解得x 1 =-4,x 2 =1...

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