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解方程:(1)2x2+4x%1=0;(2)4(2x%1)2=9(x+4)2

(1)∵a=2,b=-4,c=-1,∴△=(-4) 2 -4×2×(-1)=24,∴x= 4± 24 2×2 = 4± 2 6 4 = 2± 6 2 ,∴x 1 = 2+ 6 2 ,x 2 = 2- 6 2 ;(2)方程两边开方,得2x+1=±(x-4),即2x+1=x-4或2x+1=-(x-4),解得x 1 =-5,x 2 =1.

(1)(x-1) 2 =4,开方得:x-1=2,x-1=-2,解得:x 1 =3,x 2 =-1;(2)2x 2 -4x+1=0,b 2 -4ac=(-4) 2 -4×2×1=8,x= 4± 8 2×2 x 1 = 2+ 2 2 ,x 2 = 2- 2 2 .

(1)(x-1)2=4,开方得:x-1=2,x-1=-2,解得:x1=3,x2=-1;(2)2x2-4x+1=0,b2-4ac=(-4)2-4×2×1=8,x=4±82×2x1=2+22,x2=2?22.

(1)∵a=2,b=-4,c=-1,∴△=(-4)2-4×2×(-1)=24,∴x=4±242×2=4± 264=2±62,∴x1=2+62,x2=2?62;(2)方程两边开方,得2x+1=±(x-4),即2x+1=x-4或2x+1=-(x-4),解得x1=-5,x2=1.

(1)3/4x+1/2x=9/4 5x/4=9/4 x=9/5 (2)4/5x×〔1/2+0.4〕=4.32 4x/5=4.32÷0.9 x=4.8X5/4 x=6

(1)x 2 -2x+1=9,移项得:x 2 -2x-8=0,即(x-4)(x+2)=0,可得x-4=0或x+2=0,解得:x 1 =4,x 2 =-2;(2)去分母得:4x 2 +2x-1=0,这里a=4,b=2,c=-1,∵b 2 -4ac=2 2 -4×4×(-1)=20>0,∴x= -2± 20 8 = -1± 5 4 ,则x 1 = -1+ 5 4 ,x...

①方程两边开平方,得2x-1=±3,解得x1=2,x2=-1;②移项,得x2+3x=4配方,得x2+3x+94=4+94(x+32)2=254,开平方,得x+32=±52解得x1=1,x2=-4;③∵a=1,b=-2,c=-8,△=(-2)2-4×1×(-8)=36∴x=2±362,解得x1=4,x2=-2;④移项,化系数为“1”,得x2-2...

(1)(x+1)2+2(x+1)-4=0(x+1)2+2(x+1)+1-1-4=0;(x+1+1)2=5,x+2=±5,x1=-2+5,x2=?2?5(2)2x2+1=3x2x2-3x+1=0(2x-1)(x-1)=0x1=1,x2=12(3)(2x-1)2=x2+4x+44x2-4x+1=x2+4x+43x2-8x-3=0x1=3,x2=-13

(1)因式分解得,(2x+1)(x+3)=0,解得,x1=12,x2=3;(2)移项得,(x-1)2+2(x-1)=0,提公因式得,(x-1)(x-1+2)=0,解得,x1=1,x2=-1;(3)移项得,x(2x+3)-(4x+6)=0,提公因式得,(2x+3)(x-2)=0,解得,x1=-32;x2=2;...

(1) (2x+3)^2=4(2x+3) (2x+3)^2-4(2x+3)=0 (2x+3)(2x+3-4)=0 (2x+3)(2x-1)=0 2x+3=0或2x-1=0 所以x=-3/2或x=1/2 (2) 2(x-3)=x^2-9 2(x-3)=(x+3)(x-3) (x-3)(x+3-2)=0 (x-3)(x+1)=0 x-3=0或x+1=0 所以x=-1或x=3 (3) 4x^2-4x+1=0 (2x-1)^2=0 2x-1=...

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