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解方程:x/(x%2)+(x%9)/(x%7)=(x+1)/(x%1)+(x%8)/(...

解: x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6) 因为x/x-2=(x-2+2)/x-2=1+2/x-2.其他类似。 即 1+2/(x-2)+1-2/(x-7)=1+2/(x-1)+1-2/(x-6) 1/(x-2)-1/(x-7)=1/(x-1)-1/(x-6) 可得-5/(x-2)(x-7)=-5/(x-1)(x-6) (x-2)(x-7)=(x-1)(x-6) 化简...

解: x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6) 1+2/(x-2)+1-2/(x-7)=1+2/(x-1)+1-2/(x-6) 1/(x-2)-1/(x-7)=1/(x-1)-1/(x-6) 1/(x-2)+1/(x-6)=1/(x-1)+1/(x-7) (2x-8)/(x^2-8x+12)=(2x-8)/(x^2-8x+7) 由于x^2-8x+12不等于x^2-8x+7 因此,只...

(x+1)(x+9)(x+3)(x+8)+(x+8)(x+2)(x+3)(x+8)=(x+2)(x+2)(x+8)(x+9)+(x+7)(x+2)(x+9)(x+3) 合并同类项 (x+1)(x+9)(x+3)(x+8)-(x+2)(x+2)(x+8)(x+9)=-(x+8)(x+2)(x+3)(x+8)+(x+7)(x+2)(x+9)(x+3) (x+9)(x+8)=(x+2)(x+3) 12x=66 x=11/2

1) 设x/(x+1)=y 则原式为 y+4/y=4 (把4提取出来) 两边同乘以y ,则得到 y^2+4=4y 所以y^2-4y+4=0 解得y=2 所以x/(x+1)=2, 解得x=-2 2)由裂项法,(x+7)/(x+6)=1+1/(x+6) 可得 原式为 1+1/(x+6)+1+1/(x+8)=1+1/(x+9)+1+1/(x+5) 所以有 1/(x...

太懒了吧,小学的通分问题

x/x+1+1=7/8 解:x/x+1=7/8-1 x/x+1=-1/8 x=(-1/8)×(x+1) x=-1/8x-1/8 x+1/8x=-1/8 9/8x=-1/8 x=-1/8÷9/8 x=-1/9

(x-6)/(x-7)+1/(7-x)=8 解:(x-6)/(x-7)-1/(x-7)=8 两边同时乘以x-7,得 x-6-1=8(x-7) x-7=8x-56 7x=56-7 7x=49 x=7 题目有问题?

x乘(x+1)乘(x+2)=504 x(x+1)(x+2)=504 x(x+1)(x+2)=7×8×9 x=7

(x+2)/(x+1)-(x+4)/(x+3)=(x+6)/(x+5)-(x+8)/(x+7) 1-1/(x+1)-1-1/(x+3)=1+1/(x+5)-1-1/(x+7) 1/(x+1)-1/(x+3)=1/(x+5)-1/(x+7) 2/((x+1)(x+3))=2/((x+5)(x+7)) (x+1)(x+3)=(x+5)(x+7) x^2+4x+3=x^2+12x+35 8x=-32 x=-4

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