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1/X^2%4X+4%X/X^%4+1/2X+4=?

1/X^2-4X+4-X/X^2-4+1/2X+4 =1/(x-2)^2-x/(x+2)(x-2)+1/2(x+2) =(2x+4-2X^2+4x+x^2-4x+4)/2(x+2)(x-2)^2 =-(x-4)(x+2)/2(x+2)(x-2)^2 =-(x-4)/2(x-2)^2

(x+2/x^2-2x)-(x-1/x^2-4x+4)/(4-x/x) =((x+2)/[x(x-2)]-((x-1)/(x-2)^2)/[(4-x)/x] =[(x^2-4)-x(x-1)]/[x(x-2)^2]/[(4-x)/x] =(x-4)/{x(x-2)^2]* x/(4-x) =-1/(x-2)^2

1/2x(x-2)=x²-4x+4 1/2x(x-2)=(x-2)² x(x-2)=2(x-2)² 2(x-2)²-x(x-2)=0 (x-2)[2(x-2)-x]=0 (x-2)(x-4)=0 x1=2,x2=4

两边乘以(x+2)(x-2)得 x-2+4x-2x-4=x²-4 x²-3x+2=0 (x-2)(x-1)=0 ∴x=2 x=1 检验:x=2是增根 ∴方程的解是x=1

(x+2)/(x²-2x)-(x-1)/(x²-4x+4) =(x+2)/[x(x-2)]-(x-1)/(x-2)² =[(x+2)(x-2)-x(x-1)]/[x(x-2)²] =(x²-4-x²+x)/[x(x-2)²] =(x-4)/[x(x-2)²] 很高兴为您解答,祝你学习进步>学习宝典】团队为您答题。 有...

=[(x+2)/x(x-2)-(x-1)/(x-2)²] ×(x+2)(x-2)/(4-x) =[(x+2)(x-2)-x(x-1)]/x(x-2)² ×(x+2)(x-2)/(4-x) =(x²-4-x²+x)/x(x-2)×(x+2)/(4-x) =(x-4)/x(x-2)×(x+2)/(4-x) =-(x+2)/x(x-2)

4x•x+(2x-1)(1-2x) =4x^2-(2x-1)(2x-1) =4x^2-(4x^2-2x+1) =4x^2-4x^2+4x-1 =4x-1 当x=1/40时 原式=4*1/40-1 =1/10-1 =-9/10

原式=[(x+2)/x(x-2)-(x-1)/(x-2)²]×[x/(x-4)] =[(x²-4-x²+x)/x(x-2)²]×[x/(x-4)] =[(x-4)/x(x-2)²]×[x/(x-4)] =1/(x-2)²

(2x-1)^2=x^2+4x+4 4x^2-4x+1=x^2+4x+4 4x^2-x^2-4x-4x+1-4=0 3x^2-8x-3=0 (3x+1)(x-3)=0 3x+1=0或x-3=0 得x=-1/3或x=3

[(2x-1)/(x-1)-x-1]÷(x^2-4x+4)/(x-1) =[(2x-1)-(x+1)(x-1)]÷(x-2)^2 =(2x-x^2)÷(x-2)^2 =x(2-x)÷(x-2)^2 =x/(2-x) =(√2+2)/[2-(√2+2)] =(√2+2)/(-√2) =-1-√2 如果不懂,请追问,祝学习愉快!

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