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1/x+1+1/x+4=1/x+2+1/x+3怎么算?

解: 1/(x-1)+1/(x-4)=1/(x-2)+1/(x-3) (x-4+x-1)/(x-1)(x-4)=(x-3+x-2)/(x-2)(x-3) (2x-5)/(x-1)(x-4)=(2x-5)/(x-2)(x-3) 因为(x-1)(x-4)=x^2-5x+4 (x-2)(x-3)=x^2-5x+6 所以 (x-1)(x-4)不等于(x-2)(x-3) 因此 只有2x-5=0 解得 x=5/2

(x-1)(x-2)(x-3)(x-4) =[(x-1)(x-4)][(x-2)(x-3)] =[x^2-5x+4][x^2-5x+6] =(x^2-5x)^2+10(x^2-5x)+24 =x^4-10x^3+35x^2-50x+24

(X+1)/(X-1)-4/(X²-1)=1 两边同乘以(X²-1),得 (x+1)²-4=x²-1 2x-3=-1 x=1 检验知x=1是增根 所以,原方程无解

x-1/3+2/3=5/4 x+1/3=5/4 x=5/4-1/3 x=11/12

1/(x+1)-1/(x+2)=1/(x+3)-1/(x+4) (x+2)/[(x+1)(x+2)]-(x+1)/[(x+1)(x+2)] =(x+4)/[(x+3)(x+4)]-(x+3)/[(x+3)(x+4)] 1/[(x+1)(x+2)]=1/[(x+3)(x+4)] (x+1)(x+2)=(x+3)(x+4) x^2+x+2x+2=x^2+3x+4x+12 x^2+3x+2=x^2+7x+12 4x=-10 x=-5/2

100个数相加,第1个数是1,99次循环: for(i=0,s=1.0;i

这道题要求计算能力很强 3/x+1/(x-1)+4/(x-2)+4/(x-3)+1/(x-4)+3/(x-5)=0 [3/x+3/(x-5)]+[1/(x-1)+1/(x-4)]+[4/(x-2)+4/(x-3)]=0 (6x-15)/(x^2-5x)+(2x-5)/(x^2-5x+4)+(8x-20)/(x^2-5x+6)=0 (2x-5)[3/(x^2-5x)+1/(x^2-5x+4)+4/(x^2-5x+6)]=0 所...

由于 (1-x)(1+x+x^2)=1-x^3 1+x+x^2+x^3+x^4=(1-x^3)/(1-x)+x^3*(1+x) =(1-x^3)/(1-x)+[x^3*(1+x)*(1-x)]/(1-x) =(1-x^3)/(1-x)+[x^3*(1-x^2)]/(1-x) =(1-x^3)/(1-x)+(x^3-x^5))/(1-x) =(1-x^3+x^3-x^5)/(1-x) =(1-x^5)/(1-x)

x=1=(-1+3)/2=(0+2)/2;x=2=(1+3)/2=(0+4)/2;x=3=(1+5)/2=(2+4)/2。 一般地,方程1/(x-a)-1/(x-b)=1/(x-c)-1/(x-d)(其中a+d=b+c)的解为x=(a+d)/2=(b+c)/2。 解为x=-5的分式方程可以为1/x-1/(x+2)=1/(x+8)-1/(x+10)等。

x+3/x+4-x+4/x+5=x+1/x+2-x+2/x+3 (x²+8x+15-x²-8x-16)/(x+4)(x+5)=(x²+4x+3-x²-4x-4)/(x+2)(x+3) -1/(x²+9x+20)=-1/(x²+5x+6) ∴x²+9x+20=x²+5x+6 9x-5x=6-20 4x=-16 x=-4 ∵x=-4原方程无意义, ∴原方程...

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