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1/x+1+1/x+4=1/x+2+1/x+3怎么算?

(x+1)/2+(x-4)/3=2 3(x+1)+2(x-4)=12 3x+3+2x-8=12 5x-5=12 5x=17 x=17/5

因为X+1/x=3, 所以(x+1/x)^2=9 x^2+2+1/x^2=9 x^2+1/x^2=7 两边同时乘x^2 x^4+1=7x^2 x^4=7x^2-1 把上式带入后 x^2/7x^2-1+1=1/7

1/(x+2)-1/(x+3)-1/(x+4)+1/(x+5)=0 1/(x+2)-1/(x+3)=1/(x+4)-1/(x+5) 1/(x+2)(x+3)=1/(x+4)(x+5) (x+2)(x+3)=(x+4)(x+5) x²+5x+6=x²+9x+20 4x=-14 x=-3.5

设(x²+1)/(x+1)=y ∴y+3/y=4 y²-4y+3=0 (y-3)(y-1)=0 ∴y=3 y=1 ∴(x²+1)/(x+1)=3 (x²+1)/(x+1)=1 x²+1=3x+3 x²+1=x+1 x²-3x-2=0 x²-x=0 x=(3+√17)/2 x=(3-√17)/2 x=0 x=1

这道题要求计算能力很强 3/x+1/(x-1)+4/(x-2)+4/(x-3)+1/(x-4)+3/(x-5)=0 [3/x+3/(x-5)]+[1/(x-1)+1/(x-4)]+[4/(x-2)+4/(x-3)]=0 (6x-15)/(x^2-5x)+(2x-5)/(x^2-5x+4)+(8x-20)/(x^2-5x+6)=0 (2x-5)[3/(x^2-5x)+1/(x^2-5x+4)+4/(x^2-5x+6)]=0 所...

1/1-x+1/1+x =(1+x)/(1-x)(1+x)+(1-x)/(1+x)(1-x) =(1+x+1-x)/(1+x)(1-x) =2/(1+x)(1-x) =2/(1-x^2) 1/1-x+1/1+x+2/1+x^2+4/1+x ^4 =(1/1-x+1/1+x)+2/1+x^2+4/1+x ^4 =[2/(1-x^2)+2/(1+x^2)]+4/(1+x ^4) =4/(1-x^4)+4/(1+x ^4) =8/(1-x^8)

1/(1-x)+1/(1+x)+2/(1+x²)+4/(1+x⁴) =(1+x+1-x)/(1-x²)+2/(1+x²)+4/(1+x) =2/(1-x²)+2/(1+x²)+4/(1+x⁴) =[2(1+x²)+2(1-x²)/(1-x⁴)+4/(1+x⁴) =4/(1-x⁴)+4/(1+x⁴) =[4(1-...

x+3/x+4-x+4/x+5=x+1/x+2-x+2/x+3 (x²+8x+15-x²-8x-16)/(x+4)(x+5)=(x²+4x+3-x²-4x-4)/(x+2)(x+3) -1/(x²+9x+20)=-1/(x²+5x+6) ∴x²+9x+20=x²+5x+6 9x-5x=6-20 4x=-16 x=-4 ∵x=-4原方程无意义, ∴原方程...

两边乘以4,得 2(x+1)-4=8+(2-x) 去括号得 2x+2-4=8+2-x 移项得 2x+x=8+2-2+4 合并同类项得 3x=12 两边除以3得 x=4

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