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12.5x3.2x0.9怎样简便?

12.5x3.2x0.9怎样简便? 12.5x3.2x0.9 =12.5*8*0.4*0.9 =10*0.36 =3.6

设f(x)= x^6-2x^5+5x^3+1 f(0)= 1 f(-1)= 1+2-5+1= -1 ∴ f(-1)<0<f(0) ∵ 函数为连续函数 ∴ 函数在(-1,0)间有零点 ∴ 方程x^6-2x^5+5x^3+1= 0在(-1,0)内有实数根所以,原方程在R上至少有俩个实根

(12.5×8)×(0.4×0.25)

12.5X3.2x0.25 =(12.5X0.8)x(4×0.25) =10×1 =10

12.5×3.2×2.5 =12.5×0.8×4×2.5 =(12.5×0.8)×(4×2.5) =10×10 =100

12.5×3.2 =12.5×0.8××4 =40

12.5x3.2 解:简便脱式计算 =12.5x(8x0.4) =12.5x8x0.4 =100x0.4 =40 祝学习进步。

12.5x3.2x0.25 =12.5x0.8x4x0.25 =10x1 =10

12.5x3.2x2.5 =12.5x8x0.4x2.5 =(12.5x8)x(0.4x2.5) =100x1 =100

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