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2x^2+6x+2=0 解方程

x2-6x+2=0移项,得x2-6x=-2,即x2-6x+9=-2+9,∴(x-3)2=7,解得x-3=±7,即x=3±7.∴x1=3+7,x2=3-7.

6x^2+19x+10=0 (2x+5)(3x+2)=0 2x+5=0或3x+2=0 x1=-5/2,x2=-2/3 十字相乘法的方法简单来讲就是:十字左边相乘等于二次项系数,右边相乘等于常数项,交叉相乘再相加等于一次项系数。 如x^2+(m+n)x+mn=(x+m)(x+n) x^2+x-2=(x+2)(x-1).

配方啊 ( ^ 表示平方) 2X^-6X+1=0 2(X^-3X)+1=0 2(X-1.5)^-4.5+1=0 2(X-1.5)^=3.5 (X-1.5)^=1.75 答案:X1=二分之根号七+1.5 X2=二分之根号七-1.5

x^2+6x—2=0 (x+3)²=11 x=±√11-3 满意采纳奥

解法1:∵a=2,b=-6,c=3∴x=6±122×2∴x1=3+32,x2=3?32;解法2:x2-3x+3=?32x2-3x+94=?32+94(x?32)2=34x?32=±34∴x1=3+32,x2=3?32.

左==(6x^4 - 24x^3 + 24x^2) - x^3 - 12x^2 + 25x + 6 =6x^2*(x - 2)^2 - x^3 + 4x^2 - 4x - 16x^2 + 29x + 6 =6x^2*(x - 2)^2 - x(x^2 - 4x + 4) - (16x^2 - 29x - 6) =6x^2*(x - 2)^2 - x(x - 2)^2 - (x - 2)(16x + 3) =(x - 2)[6x^2*(x - 2) ...

x^2+6x+9=0 (x+3)(x+3)=0 x=-3 x^2+6x+9=0 x=-3 2x^2-x-1=0 (2x+1)(x-1)=0 x=-1/2, x=1

方程两边都乘以(x-1)(x-2),得2(x-2)-(x2+6x-9)=0,化简得:-x2-4x+5=0,解得:x=1或x=-5.经检验:x=1不是原方程的解,x=-5是原方程的解.故x=-5.

(1)移项,得2x2-6x=-1,化二次项系数为1,得x2-3x=-12,配方,得x2-3x+(32)2=-12+(32)2,即(x-32)2=74,开方,得x-32=±72,解得,x1=3+72,x2=3?72;(2)移项,得(2x-1)2-x2=0,所以(2x-1-x)(2x-1+x)=0,即(x-1)(3x-1)=0,解得,...

-2x^2+6x-50 x>3+i/2或x

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