ldcf.net
当前位置:首页 >> 6x^2%4x+1=0 >>

6x^2%4x+1=0

4x^3-2x^2 -(4x^2-1)=0 2x^2(2x-1)-(2x-1)(2x+1)=0 (2x-1)(2x^2-2x-1)=0 剩下的。。。不难了

用配方法: 6x^2-4x+1=0 x^2-2/3 x +1/6=0 x^2 - 2/3 x +1/9-1/9+1/6=0 (x-1/3)^2=1/9 - 1/6

4x²+y²-4x+10y+26=0 4x²-4x+1+y²+10y+25=0 (2x-1)²+(y+5)²=0 2x-1=0 y+5=0 x=1/2 y=-5 6x-1/5y=3+1=4

写出系数矩阵为 3 5 4 -2 2 3 2 1 4 7 6 -5 r3-2r2,r1-r2 ~ 1 2 2 -3 2 3 2 1 0 1 2 -7 r2-2r1,r1-2r3 ~ 1 0 -2 11 0-1 -2 7 0 1 2 -7 r3+r2,r2*(-1) ~ 1 0 -2 11 0 1 2 -7 0 0 0 0 得到基础解系为(2,-2,1,0)^T和(-11,7,0,1)^T

解: 1/4x²-6x+3=0 1/4x²-6x=-3 方程两边同时乘4 x²-24x=-12 x²-24x+144=-12+144 (x-12)²=132 x-12=±√132 x-12=±2√33 x=12±2√33 x1=12+2√33 x2=12-2√33 2x²-4x+1=0 2x²-4x=-1 方程两边同时除以2 x²-2x=...

可以使用约束极值函数 fmincon,代码参考 >> f = @(x) -(10*x(1)+6*x(2));>> x0 = [0,0]; % 初始值>> A = [6,2;4,6]; % 线性约束>> B = [26;36]; % 线性约束>> LB = [0,0]; % 下限>> UB = [inf,inf]; % 上限>> x = fmincon(f,x0,A,B,[],[],LB,UB...

Y1=(X+3)^2+1, Y2=-(X-2)^2-2, ∴A(-3,1),B(2,-2), 直线AB解析式Y=KX+b,得方程组: {1=-3K+b {-2=2K+b 解得:K=-3/5,b=-4/5, ∴直线AB:Y=-3/5X-4/5, 令Y=0,即-3/5X-4/5=0, X=-4/3, ∴m=-4/3。

4x²-6x-3=0 x² -3/2x -3/4 = 0 x² -3/2x +9/16 = 3/4 +9/16 x² -3/2x +9/16 = 21/16 (x - 3/4)(x - 34/) = 21/16 x - 3/4 = ±sqrt(21)/4 x = ±sqrt(21)/4 + 3/4 x1 = sqrt(21)/4 + 3/4 x2 = -sqrt(21)/4 + 3/4 网页无法打分...

网站首页 | 网站地图
All rights reserved Powered by www.ldcf.net
copyright ©right 2010-2021。
内容来自网络,如有侵犯请联系客服。zhit325@qq.com