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7分之5*11分之6*7/10 3/4*(9/10%5/6) (1/5+1/9...

(9分之8+1又7分之3+10分之6)除以(11分之3+7分之5+9分之4) =(8/9+10/7+6/10)除以(3/11+5/7+4/9) =(560/630+900/630+378/630)除以(189/693+495/693+308/693) =(1838/630)除以(993/693) =(1838/630)X(693/993) =(919/105)X(...

1/[n(n+1)(n+2)]=1/2*[1/n-2/(n+1)+1/(n+2)], 例如 ∴1/(1*2*3)+1/(2*3*4)+1/(3*4*5)+1/(4*5*6)+1/(5*6*7)+1/(6*7*8)+1/(7*8*9) =1/2*[1-2/2+1/3+1/2-2/3+1/4+1/3-2/4+1/5+……+1/7-2/8+1/9] =1/2[1-1/2-1/8+1/9] =1/2(1/2-1/72) =35/144. 后面加一...

这个题主要就是要注意:圆括号,加号、减号、乘号与取余的优先级与结合性。 其中,圆括号优先级最高,乘号和取余第二,加号和减号最低 结合性均是从左到右。 10 + 9 * ((8 + 7) % 6) + 5 * 4 % 3 * 2 + 3 =10 + 9 * (15% 6) + 5 * 4 % 3 * 2 + 3...

10分之13除7+10以分之13*7分之6 =13/10*1/7+13/10*6/7 =13/10*(1/7+6/7) =13/10 (1-6分之5×5分之3)÷4 =(1-5/6*3/5)÷4 =(1-1/2)×1/4 =1/2*1/4 =1/8 1-9分之8÷3分之4×4分之3 =1-8/9×3/4*3/4 =1-1/2 =1/2 6分之5×5分之3+7分之4+7分之3 =5/6×3/5+...

(10+10-10)÷10=1=10×10÷10 ÷10 (10+10+10)÷10=3 10+(10-10)÷10=10 10-(10+10)÷10=8 这是目前能想出的四个。

将四个数字看成一组 (1+2-3-4)+(5+6-7-8)+……+(2005+2006-2007-2008) =(-4)+(-4)+…+(-4) =(-4)*(2008/4) =-2008 这里2008/4是因为一共有2008个数,每四个数一组,当然就是2008/4组数了,每组都是-4,两者相乘即可

(1+2)+3+4+5-6-7+8-9 = 1 (1+2)+3+4-5+6+7-8-9 = 1 (1+2)+3+4*5-6*7+8+9 = 1 (1+2)+3-4-5-6-7+8+9 = 1 (1+2)+3*4*5/6*7-8*9 = 1 (1+2)-3+4-5-6+7-8+9 = 1 (1+2)-3-4+5+6-7-8+9 = 1 (1+2)-3-4+5-6+7+8-9 = 1 (1+2)-3*4*5/6+7-8+9 = 1 (1+2)-3/4-5...

拆分每个分数。记住等式: 1/(x(x+1))=1/x-1/(x+1) 所以,原等式就可以简化为1/1-1/10=0.9

脱式计算 (3/4+1/6)*2/3 =3/4*2/3+1/6*2/3 =1/2+1/9 =11/18 25*1/5-5*1/5 =5-1 =4 6/11*7/15*10 =84/33 =28/11 (1/7+1/4)*28 =1/7*28+1/4*28 =4+7 =11 (21+2/5)*5/7 =21*5/7+2/5*5/7 =15+2/7 =15又2/7 39*7/13*2/3 =14

11-10+9-8+7-6+5-4+3-2+1 =(11-10)+(9-8)+(7-6)+(5-4)+(3-2)+1 =1+1+1+1+1+1 =6

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