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X×(X+1)×(X+2)×(X+3)=360 这个怎么算?

提公因式

[x(x+3)][(x+1)(x+2)]=360(这样做是为了让一次项系数相等) (x^2+3x)(x^2+3x+2)-360=0 (把x^2+3x看成一个整体) (x^2+3x)^2+2(x^2+3x)-360=0 (x^2+3x-18)(x^2+3x+20)=0 (x-3)(x+6)(x^2+3x+20)=0 x=3或x=-6

将式子变型为x(x+3)(x+1)(x+2)=360(x²+3x)(x²+3x+2)=360[(x²+3x+1)-1][(x²+3x+1)+1]=360(x²+3x+1)²-1²=360(x²+3x+1)²=361x²+3x+1=±19 将正负19分别代入得 x²+3x+20=0因为3²-4×20<...

(x+1)(x+2)(x+3)(x+4)=360 =[(x+1)(x+4)][(x+2)(x+3)]-360 =(x²+5x+4)(x²+5x+6)-360 =(x²+5x)²+10(x²+5x)+24-360 =(x²+5x)²+10(x²+5x)-336 =(x²+5x-14)(x²+5x+24) =(x-2)(x+7)(x²+5x+24)

将式子变型为x(x+3)(x+1)(x+2)=360(x??+3x)(x??+3x+2)=360[(x??+3x+1)-1][(x??+3x+1)+1]=360(x??+3x+1)??-1??=360(x??+3x+1)??=361x??+3x+1=±19 将正负19分别代入得 x??+3x+20=0因为3??-4×20<0判别式小于0,无实数解。 x??+3x-18=0(x+6)(x-3)=0...

x和乘号混淆了 360=2X2X2X3X3X5 2X2=4 2X3=6 36=3X4X5X6 所以x=3

x(x-1)(x-2)(x-3)等于360 (x²-3x)(x²-3x+2)=360 (x²-3x)²+2(x²-3x)=360 (x²-3x)²+2(x²-3x)+1=360+1 (x²-3x+1)²=361 x²-3x+1=±19 ∴ ① x²-3x+1=19 x²-3x-18=0 (x+3)(x-6)=0 ...

题目对吗? 是求x*(x+1)*(x+2)*(x+3)=360的正整数解吧? 360=2×2×2×3×3×5=3×4×5×6 x=3

3x+x=1080 4x=1080 x=270 你自己看看对不对

前面x.什么意思

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