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limx趋向于0 2x/sin3x

解法一:等价无穷小 lim sin3x/sin2x x→0 =lim 3x/(2x) x→0 =3/2 解法二:高中解法,运用两个重要极限的第一个重要极限 lim sin3x/sin2x x→0 =lim (3/2)[sin3x/(3x)]/[sin2x/(2x)] x→0 =(3/2)·1/1 =3/2

无穷小代换: 原式=lim (x-2x)/(x+3x) =lim -x/(4x) =-1/4

原式=lim[ln(1+2x)/x]*lim(x/sin3x)=2*(1/3)=2/3

lim(x→0)sin3x/2x =lim(x→0)(sin3x/3x)*(3/2) =lim(3x→0)(sin3x/3x)*(3/2) lim(x→0)sinx/x=1 =3/2

不懂再问望采纳

limx→0sin2x/sin3x =limx→0(sin2x/2x)*(3x/sin3x)*(2/3) limx→0sinx/x=1 就有 limx→0sin2x/sin3x=2/3

limx^2/sin^2x/3=(其中x趋近于0

lim(x->0) sin(2x)/tan(3x)=lim(x->) (2x)/(3x)=2/3 lim(x->0) sin(2x)/tan(3x)=lim(x->0) [sin(2x)]'/[tan(3x)]' =lim(x->0) 2cos(2x)/[3/cos^2(3x)]=2/3 lim(x->0) sin(2x)/tan(3x)=lim(x->0) sin(2x)cos(3x)/sin(3x) =lim(x->0) [sin(2x)cos(...

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